Respuesta :

calculista
we know that
[volume of a original cone]=(1/3)*pi*r²*h

[volume of a dilated cone]=(1/3)*pi*(r/2)²*(h/2)--->(1/8)* [(1/3)*pi*r²*h]
so
[volume of a dilated cone]=(1/8)* [volume of a original cone]

the answer is
the volume of the cone will be reduced one eighth

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